(x+2)^2+(x-2)^2=(2x)^2

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Solution for (x+2)^2+(x-2)^2=(2x)^2 equation: 



(x+2)^2+(x-2)^2=(2x)^2

We move all terms to the left:

(x+2)^2+(x-2)^2-((2x)^2)=0

determiningTheFunctionDomain
(x+2)^2+(x-2)^2-2x^2=0

We add all the numbers together, and all the variables

-2x^2+(x+2)^2+(x-2)^2=0

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